Lake Santee, Indiana

Lake Santee is an unincorporated town and census-designated place in Decatur and Franklin counties, Indiana, United States. As of the 2010 census, it had a population of 820.[3]

Lake Santee, Indiana
Location of Lake Santee in Decatur County and Franklin County, Indiana.
Lake Santee
Coordinates: 39°24′36″N 85°18′27″W
CountryUnited States
StateIndiana
CountyDecatur, Franklin
TownshipFugit, Salt Creek
Area
 • Total2.82 sq mi (7.30 km2)
 • Land2.46 sq mi (6.38 km2)
 • Water0.36 sq mi (0.92 km2)
Elevation
1,015 ft (309 m)
Population
 (2020)
 • Total889
 • Density360.94/sq mi (139.34/km2)
ZIP code
47240
FIPS code18-41444[2]

History

Lake Santee was built up in the 1960s as a housing development centered on a reservoir of the same name.[4]

Geography

Lake Santee is located at 39°24′36″N 85°18′27″W in southeastern Indiana. It is situated 13 miles (21 km) northeast of Greensburg and 12 miles (19 km) northwest of Batesville.

According to the U.S. Census Bureau, the CDP has a total area of 2.8 square miles (7.3 km2), of which 2.5 square miles (6.4 km2) is land and 0.35 square miles (0.9 km2), or 12.60%, is water. The water area consists entirely of Lake Santee, the reservoir.[5]

Demographics

Historical population
CensusPop.%±
2020889—
U.S. Decennial Census[6]

References


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